A) + 2
B) + 4
C) + 6
D) + 8
Correct Answer: C
Solution :
Key Idea: The sum of oxidation numbers of all the elements in a compound is zero. Let the oxidation number of Cr be \[x\] \[\therefore \] for\[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\] \[+\,1\times 2+2x+7(-2)=0\] \[2+2x-14=0\] \[2x=12\] \[x=6\]
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