A) chlorobenzene
B) phenyl isocyanide
C) phenyl cyanide
D) phenyl chloride
Correct Answer: B
Solution :
\[CHC{{l}_{3}}+{{C}_{6}}{{H}_{5}}N{{H}_{2}}+3NaOH\xrightarrow{{}}\] \[\underset{\text{Phenyl}\,\text{isocyanide}}{\mathop{\underset{(A)}{\mathop{{{C}_{6}}{{H}_{5}}NC}}\,}}\,+\underset{(B)}{\mathop{3NaCl}}\,+\underset{(C)}{\mathop{3{{H}_{2}}O}}\,\] Hence, product A is phenyl isocyanide.
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