BCECE Engineering BCECE Engineering Solved Paper-2008

  • question_answer 1.520 g of hydroxide of a metal on ignition gave 0.995 g of oxide. The equivalent weight of metal is                                     

    A) 1.52                       

    B)        0.995                   

    C)                        190                        

    D)        9                         

    Correct Answer: D

    Solution :

    \[\frac{{{E}_{Hydroxide}}}{{{E}_{metal}}+{{E}_{O{{H}^{-}}}}}>\frac{{{E}_{oxide}}}{{{E}_{metal}}+{{E}_{O}}}\] \[\frac{1.520}{E+17}=\frac{0.995}{E+8}\] or            \[E=9\]

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