A) an even function
B) an odd function
C) a periodic function
D) neither an even nor an odd function
Correct Answer: B
Solution :
Given, \[f(x)=\log (x+\sqrt{{{x}^{2}}+1})\] \[\Rightarrow \] \[f(-x)=\log (-x+\sqrt{{{x}^{2}}+1})\] \[\therefore \] \[f(x)+f(-x)=\log (x+\sqrt{{{x}^{2}}+1})\] \[+\log (-x+\sqrt{{{x}^{2}}+1})\] \[=\log (1)=0\] Hence, \[f(x)\] is an odd function.
You need to login to perform this action.
You will be redirected in
3 sec
