A) remain constant
B) become double
C) become one-fourth
D) None of the above
Correct Answer: A
Solution :
Key Idea At constant temperature, \[pV=\text{constant}\] On doubling p and V with constant T, the equilibrium constant \[(K)\] will remain constant pressure will never affect the value of K. It may result in the shifting of equilibrium, but not the equilibrium constant value. Temperature always changes K because on adding heat to a system in state of equilibrium will always alter the forward reaction rate differently than the reverse reaction rate. Also by doubling the volume, the concentrations of both reactants and products evenly became half. Therefore, overall there is no change in equilibrium constant value (K).
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