A) \[C{{H}_{3}}\underset{\scriptscriptstyle-}{C}OOH\]
B) \[C{{H}_{3}}\underline{C}ON{{H}_{2}}\]
C) \[C{{H}_{3}}\underline{C}{{H}_{2}}OH\]
D) \[C{{H}_{3}}\underline{C}H=C{{H}_{2}}\]
Correct Answer: C
Solution :
\[C{{H}_{3}}\underset{s{{p}^{2}}}{\mathop{\overset{O}{\mathop{\overset{|\,|}{\mathop{C}}\,}}\,}}\,-OH\] \[C{{H}_{3}}-\overset{O}{\mathop{\underset{s{{p}^{2}}}{\overset{|\,|}{\mathop{C}}}\,}}\,-N{{H}_{2}}\] \[C{{H}_{3}}-\underset{H}{\overset{H}{\mathop{\underset{|s{{p}^{3}}}{\overset{|}{\mathop{C}}}\,}}}\,-OH\] \[C{{H}_{3}}-\overset{H}{\mathop{\underset{s{{p}^{2}}}{\overset{|}{\mathop{C}}}\,}}\,=C{{H}_{2}}\]
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