A) 1 for all \[x\]
B) \[-1\]for all \[x\]
C) 1 in 2nd and 3rd quadrant
D) \[-1\]in 3rd and 4th quadrant
Correct Answer: A
Solution :
\[y={{\cos }^{-1}}(\cos x)\] \[y=\frac{-1}{\sqrt{1-{{\cos }^{2}}x}}(-\sin x)\] \[=\frac{\sin x}{\sqrt{{{\sin }^{2}}x}}\] \[=1\forall x\]
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