BCECE Engineering BCECE Engineering Solved Paper-2009

  • question_answer
    The period of the function\[f(x)=\cos e{{c}^{2}}3x+\cot 4x\]is

    A)  \[\frac{\pi }{3}\]             

    B)                         \[\frac{\pi }{4}\]                             

    C)  \[\frac{\pi }{6}\]                             

    D)         \[\pi \]

    Correct Answer: D

    Solution :

    \[f(x)=\cos e{{c}^{2}}3x+\cot 4x\] Period of \[\cos e{{c}^{2}}3x\]is \[\frac{\pi }{3}\]and \[\cot 4x\]is \[\frac{\pi }{4}.\] \[\therefore \]Period of \[f(x)=\]LCM of \[\left( \frac{\pi }{3}\text{and}\,\frac{\pi }{4} \right)\]                 \[=\frac{\text{LCM}\,\text{of}\,(\pi ,\pi )}{\text{HCF}\,\text{of}\,(3,4)}\]                 \[=\frac{\pi }{1}=\pi \]


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