A) \[y=a\,\cos bx\,\sin ct\]
B) \[y=a\sin bx\,\cos \,ct\]
C) \[y=a\,\sin (bx+ct)\]
D) \[y=a\sin (bx+ct)\,+a\,\sin \,(bx-ct)\]
Correct Answer: C
Solution :
Two superimposing waves are incident wave \[{{y}_{1}}=a\sin (\omega t-kx)\]and reflected wave\[{{y}_{2}}=a\sin (\omega t+kx)\] Then by principle of superposition \[y={{y}_{1}}+{{y}_{2}}\] \[=a[\sin (\omega t-kx)+\sin \omega t+kx)]\] \[\Rightarrow \] \[y=2a\,\cos \,kx\,\sin \,\omega t\] Therefore, option (c) does not represent a stationary wave.
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