BCECE Engineering BCECE Engineering Solved Paper-2009

  • question_answer
    A parallel plate capacitor of plate area A has a charge Q. The force on each plate of the capacitor is

    A) \[\frac{2{{Q}^{2}}}{{{\varepsilon }_{0}}A}\]                                         

    B) \[\frac{{{Q}^{2}}}{{{\varepsilon }_{0}}A}\]                           

    C) \[\frac{{{Q}^{2}}}{2{{\varepsilon }_{0}}A}\]                         

    D)         Zero

    Correct Answer: C

    Solution :

    Force on one plate due to another is \[F=QE=Q\times \frac{\sigma }{2{{\varepsilon }_{0}}}\]                 \[=Q\left[ \frac{Q}{2A{{\varepsilon }_{0}}} \right]\]                 \[=\frac{{{Q}^{2}}}{2A{{\varepsilon }_{0}}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner