BCECE Engineering BCECE Engineering Solved Paper-2010

  • question_answer
    The numerical value of charge on either plate of capacitor C shown in figure

    A) \[CE\]                                   

    B) \[\frac{CE{{R}_{1}}}{{{R}_{1}}+r}\]

    C) \[\frac{CE{{R}_{2}}}{{{R}_{2}}+r}\]                                           

    D) \[\frac{CE{{R}_{1}}}{{{R}_{2}}+r}\]

    Correct Answer: B

    Solution :

    \[{{R}_{total}}={{R}_{1}}+r\] (Since capacitor is a DC blocking element) \[V=i{{R}_{1}}\] \[V=\frac{E{{R}_{1}}}{{{R}_{1}}+r}\]         \[\left( \because \,i=\frac{E}{{{R}_{1}}+r} \right)\]                 Since,                    \[q=CV\]                 \[\Rightarrow \]               \[q=\frac{CE{{R}_{1}}}{{{R}_{1}}+r}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner