A) 5
B) 7.5
C) 15
D) 12.5
Correct Answer: C
Solution :
Total resistance of the circuit \[R+\frac{\left( {{R}_{1}}+{{R}_{2}} \right)\times {{R}_{3}}}{({{R}_{1}}+{{R}_{2}})+{{R}_{3}}}\] \[35+\frac{(15+15)\times 30}{(15+15)+30}\] \[=35+\frac{30\times 30}{30+30}=50\,\Omega \] Current in circuit, \[i=\frac{50}{50}=1A\] Current through \[{{R}_{3}}i={{i}_{2}}=\frac{1}{2}A\] Potential difference across \[{{R}_{3}}\] \[=i\times {{R}_{3}}=\frac{1}{2}\times 30=15V\]You need to login to perform this action.
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