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BCECE Engineering BCECE Engineering Solved Paper-2010

  • question_answer
    What is the correct orbital designation of an electron with the quantum number, \[n=4,l=3,m=-2,s=\frac{1}{2}?\]

    A) \[3s\]                                   

    B)  \[4f\]                   

    C) \[~5p\]                

    D)         \[6s\]

    Correct Answer: B

    Solution :

    The value of n decides the shell of electrons. The value of \[l\] decides the orbital; \[l=0\]is \[s,l=1\]is d and \[l=3\]is \[f\] Given, \[n=4,l=3,m=-2,s=-\frac{1}{2}\] \[\therefore \] It is \[4f\]orbital.


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