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BCECE Engineering BCECE Engineering Solved Paper-2010

  • question_answer
    The pH value for \[\frac{1}{1000}\text{N}-\text{KOH}\]solution is

    A)  3                                            

    B)  \[{{10}^{-11}}\]               

    C)         2                            

    D)         11

    Correct Answer: D

    Solution :

    Given, \[[OH]=\frac{1}{1000}={{10}^{-3}}N\] \[(\therefore \,KOH\xrightarrow{{}}{{K}^{+}}OH)\] \[pOH=-\log [O{{H}^{-}}]\] \[=-\log {{10}^{-3}}\] \[pOH=3\] \[pH+pOH=14\]                 or            \[pH=14-3=11\]


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