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BCECE Engineering BCECE Engineering Solved Paper-2011

  • question_answer
    The product of\[{{x}^{1/2}}.{{x}^{1/4}},{{x}^{1/8}}....\infty \]equals

    A)  0                                            

    B)         1                            

    C)         \[x\]                                      

    D)         \[\infty \]

    Correct Answer: C

    Solution :

    \[{{x}^{(1/2+1/4+1/8+...to\,\infty )}}={{x}^{\left( \frac{1/2}{1-1/2} \right)}}=x\]


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