A) \[40{}^\circ \text{ }18\]
B) \[24{}^\circ \text{ }49\]
C) \[25{}^\circ \text{ }17\]
D) \[35{}^\circ \text{ }16\]
Correct Answer: D
Solution :
\[i={{\sin }^{-1}}\left( \frac{\sqrt{3}}{2} \right)={{\sin }^{-1}}(sin{{60}^{o}})={{60}^{o}}\] \[\mu =\frac{\sin i}{\sin r}\] \[\Rightarrow \] \[\sin \,r=\frac{\sin i}{\mu }=\frac{\sin {{60}^{o}}}{1.5}=\frac{0.8660}{1.5}\] \[\sin r=0.5773\] \[r={{\sin }^{-1}}(0.5773)={{35}^{o}}16\]
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