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BCECE Engineering BCECE Engineering Solved Paper-2011

  • question_answer
    In an experiment, 20 mL of decinormal \[HCl\] solution was added to 10 mL of a decinormal \[\text{AgN}{{\text{O}}_{\text{3}}}\]solution. \[\text{AgCl}\]was precipitated out and the excess acid was titrated against a decinormal \[\text{NaOH}\] solution. Volume of \[\text{NaOH}\].required for this back titration is

    A)  10 mL 

    B)  5 mL     

    C)         20 mL                  

    D)         30 mL

    Correct Answer: A

    Solution :

                                    \[\text{10 mL 0}\text{.1 N AgN}{{\text{O}}_{\text{3}}}\]will react with 10 mL of \[\text{0}\text{.1}\,\text{N}\,\,\text{HCl}\text{.}\] \[\therefore \]  \[\text{0}\text{.1}\,\text{N}\,\text{HCl}\,\text{left = 10}\,\text{mL}\] Thus, it will neutralize 10 mL of 0.1 N NaOH.


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