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BCECE Engineering BCECE Engineering Solved Paper-2011

  • question_answer
    The pH of buffer of \[\text{N}{{\text{H}}_{\text{4}}}\text{Cl}\]type is given by

    A) \[pH=p{{K}_{b}}\]                           

    B)  \[pH=1/2p{{K}_{b}}-1/2\,\log [salt]/[base]\]

    C)  \[pH=14-p{{K}_{b}}-\log [salt]/[base]\]

    D)  \[pH=pOH-p{{K}_{b}}+\log [salt]/[base]\]

    Correct Answer: C

    Solution :

    For basic buffer, \[pOH=p{{K}_{b}}+\log \frac{[salt]}{[base]}\] \[pOH=14-pH\] or            \[pH=14-pOH\] \[\therefore \]  \[pH=14-p{{K}_{b}}-\log \frac{[salt]}{[base]}\]


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