A) \[(\sqrt{2}-1)sq\,unit\]
B) \[\text{1}\,\text{sq}\,\text{unit}\]
C) \[\sqrt{\text{2}}\,\text{sq}\,\text{units}\]
D) \[(\sqrt{2}+1)\,sq\,unit\]
Correct Answer: A
Solution :
Area \[=\int_{0}^{\pi /4}{(\cos x-\sin x)}dx=(\sqrt{2}-1)sq\] unit \[(\because \,y=\sin \,x\,and\,y=\cos x\,meet\,x=\pi /4)\]You need to login to perform this action.
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