A) \[\pi /4\]
B) \[\pi /3\]
C) \[\pi /2\]
D) None of these
Correct Answer: C
Solution :
\[y={{x}^{2}}\Rightarrow \frac{dy}{dx}=2x\Rightarrow {{m}_{1}}=2\,at(1,1)\] \[6y=7-{{x}^{3}}\Rightarrow 6\frac{dy}{dx}=-3{{x}^{2}}\] \[\Rightarrow \]\[\frac{dy}{dx}=-1/2\,\]at \[(1,1)\] \[\Rightarrow \] \[{{m}_{2}}=-1/2\] \[\therefore \] \[{{m}_{1}}{{m}_{2}}=-1\] at\[(1,1)\] \[\Rightarrow \] \[\theta =\pi /2\]You need to login to perform this action.
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