A) 0
B) \[\frac{1}{2}\]
C) \[\frac{3}{2}\]
D) \[\frac{5}{2}\]
Correct Answer: D
Solution :
Bounded area \[\left| \int_{-1}^{0}{x\,dx} \right|+\left| \int_{0}^{2}{x\,dx} \right|\] \[=\left| -\frac{1}{2} \right|+|2|=2+\frac{1}{2}=\frac{5}{2}\]You need to login to perform this action.
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