A) 3
B) 4
C) 1
D) 2
Correct Answer: C
Solution :
Required area\[=\int_{1-e}^{0}{{{\log }_{e}}(x+e)}dx\] \[=\int_{1}^{e}{\log tdx=[t\log t-t]_{1}^{e}}\] \[\text{=1}\,\text{sq}\,\text{unit}\]You need to login to perform this action.
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