question_answer

If ABCDEF is a regular hexagon with AB = a and BC = b, then CE equals

A)  b - a                                     

B)         -b                          

C)         b - 2a                                   

D)         None of these

Correct Answer: C

Solution :

In \[\Delta \Alpha \Beta C,AB+BC=AC\] \[\Rightarrow \]               \[AC=a+b\] AD is parallel to BC and AD = 2BC \[\therefore \]  \[AD=2b\] In \[\Delta ACD,AC+CD=AD\] \[\Rightarrow \]               \[CD=2b-(a+b)=b-a\] Now, \[CE=CD+DE=b-2a\]