A) \[\frac{7}{5}\]
B) \[\frac{7}{3}\]
C) \[\frac{5}{7}\]
D) \[\frac{3}{7}\]
Correct Answer: A
Solution :
Using the relation \[{{S}_{n}}=u+\frac{a}{2}(2n-1)\] As the body starts from rest, \[\therefore \] \[u=0\] So, \[{{S}_{n}}=\frac{a}{2}(2n-1)\] \[\therefore \] \[\frac{{{S}_{4}}}{{{S}_{3}}}=\frac{(2\times 4-1)}{(2\times 3-1)}=\frac{7}{5}\]
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