A) \[{{\tan }^{-1}}x+{{\cot }^{-1}}x=C\]
B) \[{{\sin }^{-1}}x+{{\sin }^{-1}}y=C\]
C) \[{{\sec }^{-1}}x+\cos e{{c}^{-1}}x=C\]
D) None of the above
Correct Answer: B
Solution :
Given, equation is\[\int_{{}}^{{}}{\frac{dy}{\sqrt{1-{{y}^{2}}}}+\int_{{}}^{{}}{\frac{dx}{\sqrt{1-{{x}^{2}}}}}=0}\] On integration, we get\[{{\sin }^{-1}}y+{{\sin }^{-1}}x=C\]
You need to login to perform this action.
You will be redirected in
3 sec
