question_answer

Among the following ions the \[p\pi -d\pi \] overlap could be present in

A)  \[NO_{2}^{-}\]

B)         \[NO_{3}^{-}\]

C)         \[PO_{4}^{3-}\]              

D)         \[CO_{3}^{2-}\]

Correct Answer: C

Solution :

In P-O bond, \[\pi \]-bond is formed by the sidewise overlapping of d-orbital of P and p-orbital of oxygen. Hence, it is formed by \[p\pi \]and \[d\pi \]overlapping. In nitrogen and carbon no vacant d-orbital is present. So, they do not form \[p\pi -d\pi \]bond.