A) \[[{{M}^{-2}}{{L}^{-3}}{{T}^{-2}}]\]
B) \[[{{M}^{-2}}{{L}^{2}}{{T}^{-1}}]\]
C) \[[{{M}^{-1}}{{L}^{3}}{{T}^{-2}}]\]
D) \[[M{{L}^{2}}{{T}^{-1}}]\]
Correct Answer: C
Solution :
\[F=\frac{Gm,{{m}_{2}}}{{{r}^{2}}}\] \[\Rightarrow \] \[G=\frac{F{{r}^{2}}}{{{m}_{1}}{{m}_{2}}}=\frac{[ML{{T}^{-2}}][{{L}^{2}}]}{[{{M}^{2}}]}\] \[=[{{M}^{-1}}{{L}^{3}}{{T}^{-2}}]\]
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