2. Solved Papers
  3. BCECE Engineering

BCECE Engineering BCECE Engineering Solved Paper-2013

  • question_answer
    In an electron microscope if the potential is increased from 20kV to 80 kV, the resolving power R of the microscope will become

    A)  \[\frac{R}{2}\]                                 

    B)         \[2R\]                  

    C)         \[4R\]                                  

    D)         \[5R\]

    Correct Answer: B

    Solution :

    Resolving power \[\propto \frac{1}{\lambda }\]and \[\propto \frac{1}{\sqrt{v}}\] \[\therefore \]  \[R.P\propto \sqrt{v}\] \[\Rightarrow \]               \[{{(R.P)}_{2}}={{(R.P)}_{1}}\times \sqrt{\frac{80kV}{20kV}}\]                 \[=2{{(R.P)}_{1}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner