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BCECE Engineering BCECE Engineering Solved Paper-2013

  • question_answer
    25 mL of an aqueous solution of \[\text{KCl}\]was found to require 20 mL of \[\text{1}\,\text{M}\,\text{AgNO}{{}_{\text{3}}}\]solution when titrated using a \[{{\text{K}}_{\text{2}}}\text{Cr}{{\text{O}}_{\text{4}}}\]as indicator. Depression in freezing point of \[\text{KCl}\]solution with 100% ionization will be [\[{{K}_{F}}={{2.0}^{o}}mo{{l}^{-1}}kg,\]molarity = molality]

    A) \[{{3.2}^{o}}\]                  

    B)        \[{{1.6}^{o}}\]                  

    C) \[{{0.8}^{o}}\]                  

    D)        \[{{5.0}^{o}}\]

    Correct Answer: A

    Solution :

    \[\frac{KCl}{{{M}_{1}}{{V}_{1}}}=\frac{AsN{{O}_{3}}}{{{M}_{2}}{{V}_{2}}}\] \[{{M}_{1}}=\frac{1\times 20}{25}\] \[=0.8\,M\] \[i=(1+x)\] \[=1+1=2\]                 \[\therefore \]  \[\Delta {{T}_{f}}=molality\times {{K}_{f}}\times i\]                                 \[=0.8\times 2\times 2\]                               \[={{3.2}^{o}}\]


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