BCECE Medical BCECE Medical Solved Papers-2001

  • question_answer
    The focal length of lens is 5 cm. If the least distance of distinct vision is 25 cm the magnification is :

    A)  2.1              

    B)  1

    C)  1.1             

    D)  6

    Correct Answer: D

    Solution :

    The magnification of a simple microscope, when virtual image is formed at least distance of distinct vision  is given by                 \[M=1+\frac{D}{f}\] Given, \[f=5\,cm,\,D=25\,cm\] \[\therefore \] \[M=1+\frac{25}{5}=1+5=6\]


You need to login to perform this action.
You will be redirected in 3 sec spinner