BCECE Medical BCECE Medical Solved Papers-2001

  • question_answer
    The force acting on a pole of pole strength 1 Am is \[{{10}^{-4}}N\]. The magnetic field at that point is :

    A)  \[11\times {{10}^{-4}}T\]

    B)  \[10\times {{10}^{-4}}T\]

    C)  \[0.1\times {{10}^{-4}}T\]

    D)  \[1\times {{10}^{-4}}T\]

    Correct Answer: D

    Solution :

    A magnetic charge (pole) placed in a magnetic field experiences a force                 \[F=mB\] Here, \[F={{10}^{-4}}N,\,m=1\,Am\] \[\therefore \] \[B=\frac{F}{m}=\frac{{{10}^{-4}}}{1}={{10}^{-4}}T\] Note: The force on positive magnetic charge is along the field and a force on a negative magnetic charge is opposite to the field.


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