A) 3-30 MHz
B) 30-300 MHz
C) 3-3000 MHz
D) 300-3000 MHz
Correct Answer: B
Solution :
TV waves range from wavelength \[{{\lambda }_{1}}\] to \[{{\lambda }_{2}}\]. Let \[{{\lambda }_{1}}=1\,m,\,\,{{\lambda }_{2}}=10\,\,m\]. Since, TV waves are electromagnetic, so they may have speed equal to that of light, i.e., \[c=3\times {{10}^{8}}m/s\] \[\therefore \] \[{{f}_{1}}=\frac{c}{{{\lambda }_{1}}}=\frac{3\times {{10}^{8}}}{1}=3\times {{10}^{8}}=300\,\,MHz\] and \[{{f}_{2}}=\frac{c}{{{\lambda }_{2}}}=\frac{3\times {{10}^{8}}}{10}=0.3\times {{10}^{8}}=30\,\,MHz\] Hence, frequency ranges from 30 MHz to 300 MHz.
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