A) sp
B) \[s{{p}^{2}}\]
C) \[s{{p}^{3}}\]
D) none of these
Correct Answer: C
Solution :
Key Idea : Hybridisation\[=\frac{1}{2}\], [No. of electron in valence shell of central atom + No. of monovalent atoms + Charge on anion - Charge on cation] For \[Xe{{O}_{4}}\] Hybridisation \[=\frac{1}{2}\,(8+0+0-0)\] = 4 \[\therefore \] \[s{{p}^{3}}\] hybridisation.
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