A) \[{{C}_{2}}{{H}_{2}}\]
B) \[N{{H}_{3}}\]
C) \[{{N}_{2}}O\]
D) None of these
Correct Answer: B
Solution :
\[N{{H}_{3}}\] is not planar molecule because it has sp hybridisation and pyramidal shape. C in \[{{C}_{2}}{{H}_{2}}\]is sp hybridised so it is planar. \[N\underset{(c)}{\mathop{\equiv }}\,\overset{\oplus }{\mathop{N}}\,-{{O}^{O-}}\] \[\underset{(a)}{\mathop{H-C\equiv C-H}}\,\]
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