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BCECE Medical BCECE Medical Solved Papers-2002

  • question_answer
    A compound contains 38.8% C, 16% H and 45.2% N. The empirical formula of the compound will be :

    A)  \[C{{H}_{5}}N\]

    B)  \[{{C}_{2}}{{H}_{5}}N\]

    C)  \[CHN\]

    D)  \[C{{H}_{10}}{{N}_{2}}\]

    Correct Answer: A

    Solution :

    Element % Relative no. of atoms Simple ratio
    C 38.8 38.8/12 = 3.2 3.2/3.2 =1
    H 16.0 16/1 = 16.0 16.0/3.2 = 5
    N 45.2 45.2/14 = 3.2 32./3.2 = 1
    \[\therefore \] Empirical formula \[=C{{H}_{5}}N\]


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