A) 10 m/s
B) 50 m/s
C) 250 m/s
D) 500 m/s
Correct Answer: B
Solution :
Key Idea: Frictional force provides the necessary centripetal force to the motor cycle to avoid skidding. Frictional force = centripetal force i.e., \[\mu R=\frac{m{{v}^{2}}}{r}\] but R = normal reaction = mg \[\therefore \] \[\mu mg=\frac{m{{v}^{2}}}{r}\] Hence, maximum speed \[{{v}_{\max }}=\sqrt{\mu rg}\] Given, \[\mu =0.5,\,\,r=500\,\,m,\,\,g=10\,m/{{s}^{2}}\] \[\therefore \] \[{{v}_{\max }}=\sqrt{0.5\times 500\times 10}\] \[=\sqrt{5\times 500}\] = 50 m/s
You need to login to perform this action.
You will be redirected in
3 sec
