A) 1.2 N-S
B) 0.3 N-s
C) 0.1 N-s
D) 0.5 N-s
Correct Answer: B
Solution :
If a constant force F is applied on a body for a short interval of time Ar, then the impulse of this force is \[F\times \Delta t\]. Suppose that mass of a body is m. On applying a constant force F for a time interval At, the body suffers a velocity change \[\Delta v\]. From Newtons second law, we have \[F=ma=m\frac{\Delta v}{\Delta t}\] \[\therefore \] \[F=ma=0.15\times 20=3\,N\] Impulsive force \[=F\Delta t=3\times 0.1=0.3\,N-s\]
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