A) 500 \[\mu A\]
B) 0.25 \[\mu A\]
C) 0.01 \[\mu A\]
D) 100 \[\mu A\]
Correct Answer: A
Solution :
From the relation \[V=\,i\,R\] We have, V = 0.01 volt, \[R=1000\,\,\Omega \] \[\therefore \] \[\Delta {{i}_{g}}=\frac{V}{R}=\frac{0.01}{1000}={{10}^{-5}}A\] Also from definition of AC current gain, \[\beta \] is the ratio of change in collector current to change in base current at a constant collector to emitter voltage. That is \[\beta =\frac{\Delta {{i}_{C}}}{\Delta {{i}_{B}}}\] \[\Rightarrow \] \[\Delta {{i}_{C}}=\beta \,\,\Delta {{i}_{B}}\] \[=50\times {{10}^{-5}}=500\,\,\mu A\]
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