A) 1
B) zero
C) 1.5
D) 2
Correct Answer: C
Solution :
Key Idea: Write the electronic configuration of \[{{O}_{2}}^{-}\] as per molecular orbital theory and then find bond order. \[{{O}_{2}}^{-}=8+8+1=\sigma 1{{s}^{2}},\sigma {{1}^{*}}{{s}^{2}},\sigma 2{{s}^{2}},\sigma {{2}^{*}}{{s}^{2}}\], \[\sigma p_{z}^{2},\pi 2p_{x}^{2},{{\pi }^{*}}2p_{y}^{2},\,{{\pi }^{*}}2p_{x}^{2},\,{{\pi }^{*}}2p_{y}^{1}\] Bond order \[=\frac{1}{2}\] [No. of electron in bonding molecular orbital - No. of electron in antibonding molecular orbital] \[=\frac{1}{2}[10-7]\] \[=\frac{3}{2}=1.5\]
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