2. Solved Papers
  3. BCECE Medical

BCECE Medical BCECE Medical Solved Papers-2002

  • question_answer
    At \[{{25}^{o}}C\,{{K}_{a}}\] for \[C{{H}_{3}}COOH\] is \[1.8\times {{10}^{-5}}\] and \[{{K}_{b}}\] for \[N{{H}_{4}}OH\] is also \[1.8\times {{10}^{-5}}\]. The nature of aqueous solution of \[C{{H}_{3}}COON{{H}_{4}}\] is :

    A)  neutral         

    B)  basic

    C)  acidic          

    D)  amphoteric

    Correct Answer: A

    Solution :

    Key Idea: Write hydrolysis reaction and then compare \[{{K}_{a}}\] and \[{{K}_{b}}\] to decide nature of resulting solution. \[\underset{\begin{smallmatrix}  ammonium \\  acetate \end{smallmatrix}}{\mathop{C{{H}_{3}}COON{{H}_{4}}}}\,+{{H}_{2}}O\underset{acetic\text{ }acid}{\mathop{C{{H}_{3}}COOH}}\,\] \[\underset{\begin{smallmatrix}  ammonium \\  hydroxide \end{smallmatrix}}{\mathop{+\text{ }N{{H}_{4}}OH}}\,\] Given    \[{{K}_{a}}\] for \[C{{H}_{3}}COOH=1.8\times {{10}^{-5}}\]                 \[{{K}_{b}}\], for \[N{{H}_{4}}OH=1.8\times {{10}^{-5}}\] \[\because \] value of \[{{K}_{a}}\] and \[{{K}_{b}}\]is same. \[\therefore \] solution is neutral.


You need to login to perform this action.
You will be redirected in 3 sec spinner