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BCECE Medical BCECE Medical Solved Papers-2002

  • question_answer
    The enthalpy and entropy change for a reaction is \[-2.5\times {{10}^{3}}\,cal\] and 7.4 cal \[{{\deg }^{-1}}\]respectively. At 298 K the reaction is:

    A)  reversible

    B)  irreversible

    C)  spontaneous

    D)  non-spontaneous

    Correct Answer: C

    Solution :

    Key Idea: Any reaction is spontaneous when \[\Delta G\] is negative Given    \[\Delta H=-2.5\times {{10}^{3}}cal\]                 \[\Delta S=7.4\,\,cal\,\,{{\deg }^{-1}}\]                 \[T=298\,K\]                 \[\Delta G=\Delta H-T\Delta S\]                 \[=(-2.5\times {{10}^{3}})-(298\times 7.4)\]                 \[=-2500-2205\]                 = 4705 cal The reaction is spontaneous because \[\Delta G\] is negative.


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