A) \[\frac{18.03}{17.03}\]
B) \[\frac{17.03}{18.03}\]
C) \[\frac{18.03}{19.83}\]
D) \[\frac{15.03}{17.03}\]
Correct Answer: C
Solution :
Weight of wax in air, \[{{W}_{a}}=18.03\,g\] Weight of metal piece in water = 17.03 g Weight of metal piece and wax in water = 15.23g Weight of wax in water \[{{W}_{w}}=15.23-17.03=-1.8\,\,g\] Therefore, specific gravity of wax \[=\frac{weight\text{ }of\text{ }wax\text{ }in\text{ }air}{weight\text{ }of\text{ }wax\text{ }in\text{ }air-weight\text{ }of\text{ }wax\text{ }in\text{ }water}\]\[=\frac{18.03}{18.03-(-1.8)}\] \[=\frac{18.03}{19.83}\]
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