BCECE Medical BCECE Medical Solved Papers-2003

  • question_answer
    The refractive index of a material is given by the equation \[n=\frac{A+B}{{{\lambda }^{2}}}\], where A and B are constants. The dimensional formula for B is:

    A)  \[[{{M}^{0}}{{L}^{2}}{{T}^{-1}}]\]    

    B)  \[[{{M}^{0}}{{L}^{-2}}{{T}^{0}}]\]

    C)  \[[{{M}^{0}}{{L}^{2}}{{T}^{-2}}]\]

    D)  \[[{{M}^{0}}{{L}^{0}}{{T}^{0}}]\]

    Correct Answer: D

    Solution :

    Key Idea: Every equation relating physical quantities should be in dimensional balance. The given equation is \[n=\frac{A+B}{{{\lambda }^{2}}}\] where A and B are constants. The dimensions of all the terms on both sides should be same i.e, \[[B]=[A]=[n{{\lambda }^{2}}]\] \[\therefore \] \[[B]=[{{M}^{0}}{{L}^{0}}{{T}^{0}}]\,[{{L}^{2}}]\] \[=[{{M}^{0}}{{L}^{2}}{{T}^{0}}]\]


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