A) 0.0797 kcal
B) -0.0797 kcal
C) 1.435 kcal
D) -1.435 kcal
Correct Answer: B
Solution :
Key Idea: Enthalpy change per gram water is calculated by dividing \[\Delta \,H\] by molecular mass of water. Given \[\Delta H=1.4354\,\,kcal\,\,mo{{l}^{-1}}\] \[=-\frac{1.4354}{18}=-0.0797\,k\,cal\,{{g}^{-1}}\]You need to login to perform this action.
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