BCECE Medical BCECE Medical Solved Papers-2004

  • question_answer
    The current in a coil decreases from 1 A to 0.2 A in 10 s. The coefficient of self-inductance, if induced emf is 0.4 V, is :

    A) 5 H            

    B) 3 H

    C) 4 H             

    D) 2 H

    Correct Answer: A

    Solution :

    Key Idea: cm/induced in the circuit is directly proportional to the rate of change of current. emf induced oc rate of change of current i.e.,        \[e\propto \frac{di}{dt}\] when the proportionality constant is removed, the some constant L comes here. Hence,  \[e=-L\frac{di}{dt}\] ... (i) Given,   e = 0.4V,                 \[\frac{di}{dt}=\frac{0.2-1}{10}=-\frac{9.8}{10}=-0.08\,A/s\] \[\therefore \] \[L=\frac{0.4}{0.08}=5\,H\] Note: The minus sign in Eq. (i) is a reflection of Lenzs law.


You need to login to perform this action.
You will be redirected in 3 sec spinner