A) 2\[\Omega \]
B) 14\[\Omega \]
C) 4\[\Omega \]
D) 10\[\Omega \]
Correct Answer: D
Solution :
In series L- R circuit, impedance is given by \[Z=\sqrt{{{R}^{2}}+X_{L}^{2}}\] where R is the resistance and X^ the inductive reactance. Given, \[R=8\,\,\Omega ,\,\,{{X}_{L}}=6\,\,\Omega \] \[\therefore \] \[Z=\sqrt{{{(8)}^{2}}+{{(6)}^{2}}}\] \[=\sqrt{64+36}\] \[=\sqrt{100}\] \[=10\,\,\Omega \] Note: Inductive reactance \[{{X}_{L}}\], is zero, then circuit is purely resistive.
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