A) 1 L
B) 11.2 L
C) 22.4L
D) 4L
Correct Answer: A
Solution :
Key Idea : (i) Molecular weight \[=2\times \] vapour density (ii) Molecular weight in gram = 22.4 L at STP Given vapour density = 11.2 Molecular weight \[=2\times 11.2=22.4\] \[\therefore \] 22.4 g of gas occupies = 22.4 L at STP \[\therefore \] 1 g of gas occupies \[=\frac{22.4}{22.4}\times 1\] = 1 Lat STP
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