A) \[C{{H}_{3}}C{{H}_{2}}-I\] and \[C{{H}_{3}}C{{H}_{2}}OH\]
B) \[C{{H}_{2}}-C{{H}_{2}}-OH\]
C) \[C{{H}_{3}}-C{{H}_{2}}-I\]
D) none of the above
Correct Answer: C
Solution :
Key Idea: Ether on reaction with excess of \[HI\]produce two molecules of alkyl halide \[\underset{\downarrow }{\mathop{\underset{diethyl\text{ }ether}{\mathop{C{{H}_{3}}-C{{H}_{2}}-}}\,O-C{{H}_{2}}-C{{H}_{3}}-2HI}}\,\] 1 \[\underset{ethyl\text{ }iodide}{\mathop{2{{C}_{2}}{{H}_{5}}I}}\,\,\,+{{H}_{2}}O\] When equimolar quantities of ether and \[HI\]are present, then one molecule of alkyl halide and one molecule of alcohol are formed.
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