A) \[N{{a}_{2}}C{{r}_{2}}{{O}_{7}}\] and \[NaOH\]
B) \[N{{a}_{2}}C{{r}_{2}}{{O}_{7}}\] and dil. \[{{H}_{2}}S{{O}_{4}}\]
C) \[NaOH\]
D) Fe in presence of \[NaOH\]
Correct Answer: B
Solution :
Key Idea: \[{{1}^{o}}\] alcohol are converted into aldehyde by reaction with \[N{{a}_{2}}C{{r}_{2}}{{O}_{7}}\] and \[{{H}_{2}}S{{O}_{4}}\] \[\underset{ethyl\text{ }alcohol}{\mathop{C{{H}_{3}}C{{H}_{2}}OH}}\,+[O]\xrightarrow{N{{a}_{2}}C{{r}_{2}}{{O}_{7}}+{{H}_{2}}S{{O}_{4}}}\] \[\underset{ethanal}{\mathop{C{{H}_{3}}CHO}}\,+{{H}_{2}}O\]
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