A) 300 m/s
B) \[\frac{3\pi }{6}\] m/s
C) 100 m/s
D) \[\frac{\pi }{6}\] m/s
Correct Answer: A
Solution :
Key Idea: Equating the given equation with general equation of SHM. The given equation is written as \[y=3\sin \left( 100\,t+\frac{\pi }{6} \right)\] ... (i) The general equation of simple harmonic motion is written as \[y=a\sin (\omega \,t+\phi )\] ?. (ii) Equating Eqs. (i) and (ii), we get \[a=3\], \[\omega =100\] Maximum velocity, \[v=a\omega \] \[=3\times 100\] \[=300\,m/s\]
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